On Mon, Jan 18, 2016 at 08:54:07AM +0100, Vlastimil Babka wrote:
> On 18.1.2016 8:39, Sergey Senozhatsky wrote:
> > On (01/18/16 16:11), Minchan Kim wrote:
> > [..]
> >>> so, even if clear_bit_unlock/test_and_set_bit_lock do smp_mb or
> >>> barrier(), there is no corresponding barrier from record_obj()->WRITE_ONCE().
> >>> so I don't think WRITE_ONCE() will help the compiler, or am I missing
> >>> something?
> >>
> >> We need two things
> >> 2. memory barrier.
> >>
> >> As compiler barrier, WRITE_ONCE works to prevent store tearing here
> >> by compiler.
> >> However, if we omit unpin_tag here, we lose memory barrier(e,g, smp_mb)
> >> so another CPU could see stale data caused CPU memory reordering.
> >
> > oh... good find! lost release semantic of unpin_tag()...
>
> Ah, release semantic, good point indeed. OK then we need the v2 approach again,
> with WRITE_ONCE() in record_obj(). Or some kind of record_obj_release() with
> release semantic, which would be a bit more effective, but I guess migration is
> not that critical path to be worth introducing it.
WRITE_ONCE in record_obj would add more memory operations in obj_malloc
but I don't feel it's too heavy in this phase so,
How about this? Junil, Could you resend patch if others agree this?
Thanks.
+/*
+ * record_obj updates handle's value to free_obj and it shouldn't
+ * invalidate lock bit(ie, HANDLE_PIN_BIT) of handle, otherwise
+ * it breaks synchronization using pin_tag(e,g, zs_free) so let's
+ * keep the lock bit.
+ */
static void record_obj(unsigned long handle, unsigned long obj)
{
- *(unsigned long *)handle = obj;
+ int locked = (*(unsigned long *)handle) & (1<<HANDLE_PIN_BIT);
+ unsigned long val = obj | locked;
+
+ /*
+ * WRITE_ONCE could prevent store tearing like below
+ * *(unsigned long *)handle = free_obj
+ * *(unsigned long *)handle |= locked;
+ */
+ WRITE_ONCE(*(unsigned long *)handle, val);
}
>
> Thanks,
> Vlastimil
>
> >
> > -ss
> >
>
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