Re: [RFC v2 4/4] v4l: events: Don't sleep in dequeue if none are subscribed

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On 10/02/13 15:45, Sakari Ailus wrote:
Dequeueing events was is entirely possible even if none are subscribed,
leading to sleeping indefinitely. Fix this by returning -ENOENT when no
events are subscribed.

Signed-off-by: Sakari Ailus <sakari.ailus@xxxxxxxxxxxxxxx>
---
  drivers/media/v4l2-core/v4l2-event.c | 11 +++++++++--
  1 file changed, 9 insertions(+), 2 deletions(-)

diff --git a/drivers/media/v4l2-core/v4l2-event.c b/drivers/media/v4l2-core/v4l2-event.c
index b53897e..553a800 100644
--- a/drivers/media/v4l2-core/v4l2-event.c
+++ b/drivers/media/v4l2-core/v4l2-event.c
@@ -77,10 +77,17 @@ int v4l2_event_dequeue(struct v4l2_fh *fh, struct v4l2_event *event,
  		mutex_unlock(fh->vdev->lock);

  	do {
-		ret = wait_event_interruptible(fh->wait,
-					       fh->navailable != 0);
+		bool subscribed;

Can you add an empty line here?

+		ret = wait_event_interruptible(
+			fh->wait,
+			fh->navailable != 0 ||
+			!(subscribed = v4l2_event_has_subscribed(fh)));
  		if (ret < 0)
  			break;
+		if (!subscribed) {
+			ret = -EIO;

Shouldn't this be -ENOENT?

+			break;
+		}

  		ret = __v4l2_event_dequeue(fh, event);
  	} while (ret == -ENOENT);


Regards,

	Hans
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