On Thu, Jan 13, 2011 at 8:21 AM, Jean Delvare <khali@xxxxxxxxxxxx> wrote: > My bet is that register at 0x00 is a control register, and writing bit > 7 (value 0x80) makes the chip busy enough that it can't process I2C > requests at the same time. The following naks would be until the > chip is operational again. Correct. Poking bit 7 of 0xE0:00 triggers the "send" for all the bytes that were previously loaded into the device. It puts the chip into a busy state, doing an i2c clock stretch until it is available again. During that time it cannot see any i2c traffic, which is why you are getting NAKs. Devin -- Devin J. Heitmueller - Kernel Labs http://www.kernellabs.com -- To unsubscribe from this list: send the line "unsubscribe linux-media" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
