Stefan Ringel wrote: > -----BEGIN PGP SIGNED MESSAGE----- > Hash: SHA1 > > Am 04.05.2010 21:50, schrieb Mauro Carvalho Chehab: >> Stefan Ringel wrote: >> >>>>> datagram from urb to videobuf >>>>> >>>>> urb copy to temp copy to 1. videobuf >>>>> buffer 2. audiobuf >>>>> 3. vbi >>>>> 184 Packets -------> 184 * 3072 ----------> 4. etc. >>>>> a 3072 bytes bytes >>>>> 184 * 3072 * >>>>> 3072 bytes 180 bytes >>>>> (184 bytes - 4 bytes >>>>> header ) >>>> In order to receive 184 packets with 3072 bytes each, the USB code will >>>> try to allocate the next power-of-two memory block capable of receiving >>>> such data block. As: 184 * 3072 = 565248, the kernel allocator will seek >>>> for a continuous block of 1 MB, that can do DMA transfers (required by >>>> ehci driver). On a typical machine, due to memory fragmentation, >>>> in general, there aren't many of such blocks. So, this will increase the >>>> probability of not having any such large block available, causing an >>> horrible >>>> dump at kernel, plus a -ENOMEM on the driver, generally requiring a > reboot >>>> if you want to run the driver again. >>>> >>> And direct copy from urb to videobuf/alsa/vbi in 184 Bytes segments. >>> >>> urb 1. videobuf >>> copy to 2. audiobuf >>> 3. vbi >>> 184 Packets -------> 4. etc. >>> a 3072 bytes >>> 180 Bytes (without headers) >> That's basically what that logic does. It preserves the header if you > select >> TM6000 format (so, no checks for the start of the block, etc), or copies >> just the data, if you select YUY2 or UYUV. >> >>> or how can I copy 180 Bytes Data from 184 Bytes block with an >>> anligment of 184 urb pipe (184 * 3072 Bytes)? >> A 184 x 3072 URB pipe is a big problem. We used a large pipe in the > past, and this >> won't work. For example, on a notebook I used to run some tests with 1 > GB of >> ram after starting X and do anything (like opening a browser), the URB >> allocation used to fail, as there weren't any available 1MB segment at >> the DMA area. Even without starting X, after a few tests, it would > eventually >> have fragmented the memory and the driver stops working. >> >> > and 3072 * 46 = 141312 bytes and it can through 184 ! it's 1/4 smaller. It is a worthy trial to use this value for the number of packets. Yet, as someone might have run the device on windows before, it will still need to seek for the segment start. Cheers, Mauro -- To unsubscribe from this list: send the line "unsubscribe linux-media" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
