All the details about the controls are printed in the dedicated function
print_qctrl(), use a new dedicated function named print_class_name() to
print the control class name as well, this is for symmetry but it is
also in preparation for a change which aims to abstract how the controls
are printed.
Signed-off-by: Antonio Ospite <ao2@xxxxxx>
---
utils/v4l2-ctl/v4l2-ctl-common.cpp | 7 ++++++-
1 file changed, 6 insertions(+), 1 deletion(-)
diff --git a/utils/v4l2-ctl/v4l2-ctl-common.cpp b/utils/v4l2-ctl/v4l2-ctl-common.cpp
index e2710335..5d41d720 100644
--- a/utils/v4l2-ctl/v4l2-ctl-common.cpp
+++ b/utils/v4l2-ctl/v4l2-ctl-common.cpp
@@ -403,6 +403,11 @@ static void print_qctrl(int fd, struct v4l2_query_ext_ctrl *queryctrl,
}
}
+static void print_class_name(const char *name)
+{
+ printf("\n%s\n\n", name);
+}
+
static int print_control(int fd, struct v4l2_query_ext_ctrl &qctrl, int show_menus)
{
struct v4l2_control ctrl;
@@ -415,7 +420,7 @@ static int print_control(int fd, struct v4l2_query_ext_ctrl &qctrl, int show_men
if (qctrl.flags & V4L2_CTRL_FLAG_DISABLED)
return 1;
if (qctrl.type == V4L2_CTRL_TYPE_CTRL_CLASS) {
- printf("\n%s\n\n", qctrl.name);
+ print_class_name(qctrl.name);
return 1;
}
ext_ctrl.id = qctrl.id;
--
2.20.1
