Without further ado, the following was found: Issue 1: Either B<fmod>() → B<fmod> or → I<fmod>() Issue 2: What does "cost a branch" really mean? Branch of execution? "An alternate way to express this is with I<fmod(fmod(x, y) + y, y)>, but the " "second B<fmod>() usually costs way more than the one branch."
