Hello Alex,
On Sun, Jan 22, 2023 at 10:03:46PM +0100, Alejandro Colomar wrote:
> On 1/22/23 20:31, Helge Kreutzmann wrote:
> > Without further ado, the following was found:
> >
> > Issue: How can a variable (I<preg>) free memory? Isn't it B<regfree>() which frees the memory?
>
> How about the patch below?
>
> Cheers,
>
> Alex
>
> >
> > "Supplying B<regfree>() with a precompiled pattern buffer, I<preg> will free"
> > "the memory allocated to the pattern buffer by the compiling process,"
> > "B<regcomp>()."
>
>
> diff --git a/man3/regex.3 b/man3/regex.3
> index 6f5831f24..f6faf6240 100644
> --- a/man3/regex.3
> +++ b/man3/regex.3
> @@ -240,7 +240,7 @@ .SS POSIX pattern buffer freeing
> Supplying
> .BR regfree ()
> with a precompiled pattern buffer,
> -.I preg
> +.IR preg ,
> will free the memory allocated to the pattern buffer by the compiling
> process,
> .BR regcomp ().
I don't really see a change here? It's only the markup, that changed?
Greetings
Helge
--
Dr. Helge Kreutzmann debian@xxxxxxxxxxxxx
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