$ gcc -Wall -Wextra -Werror -pedantic regex.c -o regex $ ./regex String = "1) John Driverhacker; 2) John Doe; 3) John Foo; " #0 match: rm_so = 25; rm_eo = 32; len = 7 substring = "John Do" #1 match: rm_so = 6; rm_eo = 14; len = 8 substring = "John Foo" Signed-off-by: Alejandro Colomar <colomar.6.4.3@xxxxxxxxx> --- Hello Michael, Here's the example for regex.3 :-} Best regards, Alex man3/regex.3 | 44 ++++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 44 insertions(+) diff --git a/man3/regex.3 b/man3/regex.3 index 7c5132995..94da88b7e 100644 --- a/man3/regex.3 +++ b/man3/regex.3 @@ -337,6 +337,50 @@ T} Thread safety MT-Safe .TE .SH CONFORMING TO POSIX.1-2001, POSIX.1-2008. +.SH EXAMPLES +.EX +#include <stddef.h> +#include <stdint.h> +#include <stdio.h> +#include <stdlib.h> +#include <regex.h> + +#define ARRAY_SIZE(arr) (sizeof((arr)) / sizeof((arr)[0])) + +static const char *const str = + "1) John Driverhacker;\en2) John Doe;\en3) John Foo;\en"; +static const char *const re = "John.*o"; + +int main(void) +{ + static const char *s = str; + regex_t regex; + regmatch_t pmatch[1]; + regoff_t len; + + if (regcomp(®ex, re, REG_NEWLINE)) + exit(EXIT_FAILURE); + + printf("String = \\"%s\\"\en", str); + + for (ptrdiff_t i = 0; ; i++) { + if (regexec(®ex, s, ARRAY_SIZE(pmatch), pmatch, 0)) + break; + + len = pmatch[0].rm_eo \- pmatch[0].rm_so; + printf("#%td match:\en", i); + printf("rm_so = %jd; rm_eo = %jd; len = %jd\en", + (intmax_t) pmatch[0].rm_so, + (intmax_t) pmatch[0].rm_eo, + (intmax_t) len); + printf("substring = \\"%.*s\\"\en", len, s + pmatch[0].rm_so); + + s += pmatch[0].rm_eo; + } + + exit(EXIT_SUCCESS); +} +.EE .SH SEE ALSO .BR grep (1), .BR regex (7) -- 2.28.0