Re: [RFC DO NOT MERGE] treewide: use __xchg in most obvious places

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On Tue, Jan 10, 2023 at 11:53:06AM +0100, Andrzej Hajda wrote:
This patch tries to show usability of __xchg helper.
It is not intended to be merged, but I can convert
it to proper patchset if necessary.

There are many more places where __xchg can be used.
This demo shows the most spectacular cases IMHO:
- previous value is returned from function,
- temporary variables are in use.

As a result readability is much better and diffstat is quite
nice, less local vars to look at.
In many cases whole body of functions is replaced
with __xchg(ptr, val), so as further refactoring the whole
function can be removed and __xchg can be called directly.

...

 arch_uretprobe_hijack_return_addr(unsigned long trampoline_vaddr,
 				  struct pt_regs *regs)
 {
-	unsigned long orig_ret_vaddr;
-
-	orig_ret_vaddr = regs->ARM_lr;
-	/* Replace the return addr with trampoline addr */
-	regs->ARM_lr = trampoline_vaddr;
-	return orig_ret_vaddr;
+	return __xchg(&regs->ARM_lr, trampoline_vaddr);
 }

If it's not a callback, the entire function can be killed.
And this is a good example of the function usage.
OTOH, these places might have a side effect (if it's in deep CPU
handlers), means we need to do this carefully.

...

 static inline void *qed_chain_produce(struct qed_chain *p_chain)
 {
-	void *p_ret = NULL, *p_prod_idx, *p_prod_page_idx;
+	void *p_prod_idx, *p_prod_page_idx;
 
 	if (is_chain_u16(p_chain)) {
 		if ((p_chain->u.chain16.prod_idx &
@@ -390,11 +391,8 @@ static inline void *qed_chain_produce(struct qed_chain *p_chain)
 		p_chain->u.chain32.prod_idx++;
 	}
 
-	p_ret = p_chain->p_prod_elem;
-	p_chain->p_prod_elem = (void *)(((u8 *)p_chain->p_prod_elem) +
-					p_chain->elem_size);
-
-	return p_ret;
+	return __xchg(&p_chain->p_prod_elem,
+		      (void *)(((u8 *)p_chain->p_prod_elem) + p_chain->elem_size));

Wondering if you still need a (void *) casting after the change. Ditto for the
rest of similar cases.

 }

...

Btw, is it done by coccinelle? If no, why not providing the script?

-- 
With Best Regards,
Andy Shevchenko





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