On Fri, May 20, 2022 at 02:46:20PM +0200, Geert Uytterhoeven wrote:
The "(void)" makes sure there is no return value.
Which matters if the result of a function returning void is propagated
to another function returning void.
Which, FTR, sparse also doesn't like:
error: return expression in void function
You should get this message only if the expression is itself not void.
For example:
$ cat test.c
extern void fun(void);
static void ko(int *ptr)
{
return *ptr;
}
static void ok1(int *ptr)
{
return (void) *ptr;
}
static void ok2(int *ptr)
{
return fun();
}
$ sparse test.c
test.c:5:16: error: return expression in void function
IOW, sparse warn only for the ko() but not for ok1() or ok2().
If you have a case whee it s not the case, please send me the
pre-processed file and I'll be glad to investigate.
Best regards,
-- Luc
