If the length of the name string is 1 and the value of name[0] is NULL
byte, an OOB vulnerability occurs in btf_name_valid_section() and the
return value is true, so the invalid name passes the check.
To solve this, you need to check if the first position is NULL byte and
if the first character is printable.
Suggested-by: Eduard Zingerman <eddyz87@xxxxxxxxx>
Fixes: bd70a8fb7ca4 ("bpf: Allow all printable characters in BTF DATASEC names")
Signed-off-by: Jeongjun Park <aha310510@xxxxxxxxx>
---
kernel/bpf/btf.c | 4 +++-
1 file changed, 3 insertions(+), 1 deletion(-)
diff --git a/kernel/bpf/btf.c b/kernel/bpf/btf.c
index 520f49f422fe..f1e91bf367fa 100644
--- a/kernel/bpf/btf.c
+++ b/kernel/bpf/btf.c
@@ -823,9 +823,11 @@ static bool btf_name_valid_section(const struct btf *btf, u32 offset)
const char *src = btf_str_by_offset(btf, offset);
const char *src_limit;
+ if (!*src)
+ return false;
+
/* set a limit on identifier length */
src_limit = src + KSYM_NAME_LEN;
- src++;
while (*src && src < src_limit) {
if (!isprint(*src))
return false;
--
