On Mon, 2024-04-08 at 19:20 +0200, Benjamin Tissoires wrote: [...] > That was my initial assumption too, but Alexei told me it was fine. > And I think he is correct because kfree_rcu doesn't need the rcu_head > to be initialized. > > So in the end, we initialize the memory as a work_struct, and when > that work kicks in, we reuse that exact same memory as the rcu_head. > This is fine because that work will never be reused. Oh, I get it, thank you for explanation. Thanks, Eduard
