> On Mon, May 29, 2023 at 09:00:01PM +0800, Zhangjin Wu wrote:
> > Compiling nolibc-test.c with gcc on x86_64 got such warning:
> >
> > tools/testing/selftests/nolibc/nolibc-test.c: In function 'expect_eq':
> > tools/testing/selftests/nolibc/nolibc-test.c:177:24: warning: format '%lld' expects argument of type 'long long int', but argument 2 has type 'uint64_t' {aka 'long unsigned int'} [-Wformat=]
> > 177 | llen += printf(" = %lld ", expr);
> > | ~~~^ ~~~~
> > | | |
> > | | uint64_t {aka long unsigned int}
> > | long long int
> > | %ld
> >
> > It because that glibc defines uint64_t as "unsigned long int" when word
> > size (means sizeof(long)) is 64bit (see include/bits/types.h), but
> > nolibc directly use the 64bit "unsigned long long" (see
> > tools/include/nolibc/stdint.h), which is simpler, seems kernel uses it
> > too (include/uapi/asm-generic/int-ll64.h).
> >
> > It is able to do like glibc, defining __WORDSIZE for all of platforms
> > and using "unsigned long int" to define uint64_t when __WORDSIZE is
> > 64bits, but here uses a simpler solution: nolibc always requires %lld to
> > match "unsigned long long", for others, only require %lld when word size
> > is 32bit.
> >
> > Signed-off-by: Zhangjin Wu <falcon@xxxxxxxxxxx>
> > ---
> > tools/testing/selftests/nolibc/nolibc-test.c | 4 ++++
> > 1 file changed, 4 insertions(+)
> >
> > diff --git a/tools/testing/selftests/nolibc/nolibc-test.c b/tools/testing/selftests/nolibc/nolibc-test.c
> > index d417ca5d976f..7f9b716fd9b1 100644
> > --- a/tools/testing/selftests/nolibc/nolibc-test.c
> > +++ b/tools/testing/selftests/nolibc/nolibc-test.c
> > @@ -174,7 +174,11 @@ static int expect_eq(uint64_t expr, int llen, uint64_t val)
> > {
> > int ret = !(expr == val);
> >
> > +#if __SIZEOF_LONG__ == 4 || defined(NOLIBC)
> > llen += printf(" = %lld ", expr);
> > +#else
> > + llen += printf(" = %ld ", expr);
> > +#endif
> > pad_spc(llen, 64, ret ? "[FAIL]\n" : " [OK]\n");
> > return ret;
> > }
>
> Please don't proceed like this. There's much easier to do here for a printf,
> just cast the expression to the type printf expects:
>
> - llen += printf(" = %lld ", expr);
> + llen += printf(" = %lld ", (long long)expr);
Yes, this conversion is better, my method make things more complex ;-)
Thanks,
Zhangjin
>
> Willy
