On Tue, 26 Oct 2021 18:09:22 -0700 Kalesh Singh <kaleshsingh@xxxxxxxxxx> wrote: > > delta = mult * div / 2^20 > > > > That is if mult is a power of two, then there would be no rounding > > errors, and the delta is zero, making the max infinite: That should have been (as shown in the algorithm) delta = mult * div - 2 ^ 20 As mult is 2^20 / div; and the above should end up zero if there's no rounding issues, as it would be: delta = (2^20 / div) * div - 2^20 -- Steve
