On Mon, 11 May 2020 14:59:20 +0000 David Laight <David.Laight@xxxxxxxxxx> wrote: > > > echo "Test command: $command" > > > echo > error_log > > > - (! echo "$command" >> "$3" ) 2> /dev/null > > > + (! printf "%s" "$command" >> "$3" ) 2> /dev/null > > WTF is the (! for ?? > The (...) is a subshell. > And ! inverts the exit status. > Neither is needed at all. This is done because the scripts are run with '-e' and will exit the script on any error. This particular test is examining errors in the error log. The command being written into $3 is going to fail, and return an exit code. The "(! ..)" is needed, otherwise that failure will exit out the script. -- Steve
