Re: [patch] mfd: 88pm80x: Double shifting bug in suspend/resume

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On Thu, 04 Aug 2016, Dan Carpenter wrote:

> set_bit() and clear_bit() take the bit number so this code is really
> doing "1 << (1 << irq)" which is a double shift bug.  It's done
> consistently so it won't cause a problem unless "irq" is more than 4.
> 
> Fixes: 70c6cce04066 ('mfd: Support 88pm80x in 80x driver')
> Signed-off-by: Dan Carpenter <dan.carpenter@xxxxxxxxxx>

Applied, thanks.

> diff --git a/include/linux/mfd/88pm80x.h b/include/linux/mfd/88pm80x.h
> index d409ceb..c118a7e 100644
> --- a/include/linux/mfd/88pm80x.h
> +++ b/include/linux/mfd/88pm80x.h
> @@ -350,7 +350,7 @@ static inline int pm80x_dev_suspend(struct device *dev)
>  	int irq = platform_get_irq(pdev, 0);
>  
>  	if (device_may_wakeup(dev))
> -		set_bit((1 << irq), &chip->wu_flag);
> +		set_bit(irq, &chip->wu_flag);
>  
>  	return 0;
>  }
> @@ -362,7 +362,7 @@ static inline int pm80x_dev_resume(struct device *dev)
>  	int irq = platform_get_irq(pdev, 0);
>  
>  	if (device_may_wakeup(dev))
> -		clear_bit((1 << irq), &chip->wu_flag);
> +		clear_bit(irq, &chip->wu_flag);
>  
>  	return 0;
>  }

-- 
Lee Jones
Linaro STMicroelectronics Landing Team Lead
Linaro.org │ Open source software for ARM SoCs
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