We've tried to fix the error paths in this function before, but there is still a hidden goto in the ceph_decode_need() macro which goes to the wrong place. We need to release the "req" and unlock a mutex before returning. Signed-off-by: Dan Carpenter <dan.carpenter@xxxxxxxxxx> diff --git a/net/ceph/osd_client.c b/net/ceph/osd_client.c index dbc0a73..559a832 100644 --- a/net/ceph/osd_client.c +++ b/net/ceph/osd_client.c @@ -1488,14 +1488,14 @@ static void handle_reply(struct ceph_osd_client *osdc, struct ceph_msg *msg, dout("handle_reply %p tid %llu req %p result %d\n", msg, tid, req, result); - ceph_decode_need(&p, end, 4, bad); + ceph_decode_need(&p, end, 4, bad_put); numops = ceph_decode_32(&p); if (numops > CEPH_OSD_MAX_OP) goto bad_put; if (numops != req->r_num_ops) goto bad_put; payload_len = 0; - ceph_decode_need(&p, end, numops * sizeof(struct ceph_osd_op), bad); + ceph_decode_need(&p, end, numops * sizeof(struct ceph_osd_op), bad_put); for (i = 0; i < numops; i++) { struct ceph_osd_op *op = p; int len; @@ -1513,7 +1513,7 @@ static void handle_reply(struct ceph_osd_client *osdc, struct ceph_msg *msg, goto bad_put; } - ceph_decode_need(&p, end, 4 + numops * 4, bad); + ceph_decode_need(&p, end, 4 + numops * 4, bad_put); retry_attempt = ceph_decode_32(&p); for (i = 0; i < numops; i++) req->r_reply_op_result[i] = ceph_decode_32(&p); -- To unsubscribe from this list: send the line "unsubscribe kernel-janitors" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html