Hi,
I'm reading cfs code, and get the following potential bug.
In kernel/sched_fair.c, we can get the following call thread:
1778static struct task_struct *pick_next_task_fair(struct rq *rq)
1779{
...
1787 do {
1788 se = pick_next_entity(cfs_rq);
1789 set_next_entity(cfs_rq, se);
1790 cfs_rq = group_cfs_rq(se);
1791 } while (cfs_rq);
...
1797}
925static struct sched_entity *pick_next_entity(struct cfs_rq *cfs_rq)
926{
927 struct sched_entity *se = __pick_next_entity(cfs_rq);
...
941 return se;
942}
377static struct sched_entity *__pick_next_entity(struct cfs_rq *cfs_rq)
378{
379 struct rb_node *left = cfs_rq->rb_leftmost;
380
381 if (!left)
382 return NULL;
...
385}
To manipulate cfs_rq->rb_leftmost, __dequeue_entity does the following:
365static void __dequeue_entity(struct cfs_rq *cfs_rq, struct sched_entity *se)
366{
367 if (cfs_rq->rb_leftmost == &se->run_node) {
368 struct rb_node *next_node;
369
370 next_node = rb_next(&se->run_node);
371 cfs_rq->rb_leftmost = next_node;
372 }
373
374 rb_erase(&se->run_node, &cfs_rq->tasks_timeline);
375}
Here, if se->run_node is the root rb_node, next_node will be set NULL
by rb_next.
Then __pick_next_entity may get NULL on some call, and set_next_entity
may deference
NULL value.
892static void
893set_next_entity(struct cfs_rq *cfs_rq, struct sched_entity *se)
894{
895 /* 'current' is not kept within the tree. */
896 if (se->on_rq) {
...
919 se->prev_sum_exec_runtime = se->sum_exec_runtime;
920}
Following is my patch. Please check it.
>From cb076095b9c93860afb037c50bb70c4a957c9118 Mon Sep 17 00:00:00 2001
From: Wang Sheng-Hui <crosslonelyover@xxxxxxxxx>
Date: Mon, 28 Jun 2010 19:13:33 +0800
Subject: [PATCH] avoid return NULL on root rb_node in rb_next/rb_prev
in lib/rbtree.c
Signed-off-by: Wang Sheng-Hui <crosslonelyover@xxxxxxxxx>
---
lib/rbtree.c | 6 ------
1 files changed, 0 insertions(+), 6 deletions(-)
diff --git a/lib/rbtree.c b/lib/rbtree.c
index 15e10b1..474e9fd 100644
--- a/lib/rbtree.c
+++ b/lib/rbtree.c
@@ -356,9 +356,6 @@ struct rb_node *rb_next(const struct rb_node *node)
{
struct rb_node *parent;
- if (rb_parent(node) == node)
- return NULL;
-
/* If we have a right-hand child, go down and then left as far
as we can. */
if (node->rb_right) {
@@ -385,9 +382,6 @@ struct rb_node *rb_prev(const struct rb_node *node)
{
struct rb_node *parent;
- if (rb_parent(node) == node)
- return NULL;
-
/* If we have a left-hand child, go down and then right as far
as we can. */
if (node->rb_left) {
--
1.6.3.3
--
Thanks and Best Regards,
shenghui
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