Thank you Randy, my response are inline. Please look at it.I am wondering , what else I could do get this damn! thing going?? Any clue?? On 19:33 Wed 30 Oct 2019, Randy Dunlap wrote:
Hi, On 10/30/19 2:54 AM, Bhaskar Chowdhury wrote:This patch will remove old kernels and modules directorey related to that kernel from the system by interactively and silently.Here are few interactions with the scripts 1) ✔ ~/git-linux/linux-kbuild [master|AM 1/1 ↑·59|✔] 14:52 $ ./scripts/prune-kernel -h Usage: prune-kernel [ri] -r | --remove kernel_ver modules_dir_name -i | --interactive use as interactive way ✘-1 ~/git-linux/linux-kbuild [master|AM 1/1 ↑·59|✔]14:52 $ ./scripts/prune-kernel --helpUsage: prune-kernel [ri]That "[ri]" is confusing to me.
This are the options one has to pass with the script.Like below:
-r | --remove kernel_ver modules_dir_na] -i | --interactive use as interactive way2)✘-1 ~/git-linux/linux-kbuild [master|AM 1/1 ↑·59|✔] 14:52 $ ./scripts/prune-kernel -r 5.3.3 You need to provide kernel version and modules dir name✘-1 ~/git-linux/linux-kbuild [master|AM 1/1 ↑·59|✔]14:53 $ ./scripts/prune-kernel -r You need to provide kernel version and modules dir name✘-1 ~/git-linux/linux-kbuild [master|AM 1/1 ↑·59|✔]14:54 $ ./scripts/prune-kernel -r 5.3.3 5.3.3-fooThis one above didn't remove any kernel files. Needs more testing.
It does remove but silently, as you and Bruce asked for this feature.
3) $ ./scripts/prune-kernel --remove You need to provide kernel version and modules dir name ✘-1 ~/git-linux/linux-kbuild [master|AM 1/1 ↑·59|✔] 14:55 $ ./scripts/prune-kernel --remove 5.3.3 You need to provide kernel version and modules dir name ✘-1 ~/git-linux/linux-kbuild [master|AM 1/1 ↑·59|✔] 14:55 $ ./scripts/prune-kernel --remove 5.3.3 5.3.3-foo 4)14:55 $ ./scripts/prune-kernel -i Enter kernel version to remove or blank/empty to exit: 5)14:57 $ ./scripts/prune-kernel --interactive Enter kernel version to remove or blank/empty to exit: ✔ ~/git-linux/linux-kbuild [master|AM 1/1 ↑·59|✔] 6)14:59 $ ./scripts/prune-kernel --interactive Enter kernel version to remove or blank/empty to exit:5.3.3 Please give the full modules directory name to remove:5.3.3-foo Removed kernel version:5.3.3 and associated modules:5.3.3-foo ...Done. 7)15:00 $ ./scripts/prune-kernel -i Enter kernel version to remove or blank/empty to exit:5.3.3 Please give the full modules directory name to remove:5.3.3-foo Removed kernel version:5.3.3 and associated modules:5.3.3-foo ...Done. Signed-off-by: Bhaskar Chowdhury <unixbhaskar@xxxxxxxxx> --- scripts/prune-kernel | 63 ++++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 63 insertions(+) diff --git a/scripts/prune-kernel b/scripts/prune-kernel index a25aa2160d47..a91010d0e2af 100755 --- a/scripts/prune-kernel +++ b/scripts/prune-kernel @@ -1,3 +1,66 @@ #!/bin/bash # SPDX-License-Identifier: GPL-2.0 +#This script will delete old kernels and modules directory related to it +#-h with the script will show you the help +#-r with the script take two parameter: kernel_ver and modules_dir_name +#-i with the script allow you do the removing interactive way +flag=$1 +kernel_ver=$2 +modules_dir_name=$3 +boot_dir=/boot +modules_dir=/lib/modules + +remove_old_kernel() { + cd $boot_dir + rm -If vmlinuz-$kernel_version System.map-$kernel_version config-$kernel_version + return 0 +} + +remove_old_modules_dir() { + cd $modules_dir + rm -rf $modules_version + return 0 +} + +usage() { + printf "Usage: $(basename $0) [ri] \n" + printf "\n -r | --remove kernel_ver modules_dir_name \n" + printf "\n -i | --interactive use as interactive way \n" +} + +for arg in "$@"what is the purpose (use) of "arg" here?
This variable is used in case statement below.
what is the purpose of the for loop?
It scan through all the parameters pass .
Is any 'shift' needed to consume (or discard) the first 3 positional command line arguments?
Nope, that is not required. And I haven't use any.
+do + case "$flag" in + -i | --interactive) + printf "\nEnter kernel version to remove or blank/empty to exit:%s" + read kernel_version + if [[ $kernel_version != "" ]]; then + remove_old_kernel + printf "Please give the full modules directory name to remove:%s" + read modules_version + if [[ $modules_version != "" ]]; then + remove_old_modules_dir + printf "\n\n\n Removed kernel version:$kernel_version and associated modules:$modules_version ...Done. \n"This message is only printed if $modules_version is non-empty. If it is empty, remove_old_kernel() has silently removed some kernel files (if they existed).
it will fail to remove anything if the kernel_version or modules_version are empty and importantly exit.
+ else + exit 1 + fi + fi + ;; + -h | --help) + usage + exit 1 + ;; + -r | --remove) + if [[ $# -ne 3 ]]; then + printf "You need to provide kernel version and modules dir name\n" + exit 1 + else + cd $boot_dir + rm -f $kernel_verThat 'rm' doesn't remove any files. Compare what remove_old_kernel() does.
No,it is not using that function rather take the parameter from the commandline and get into boot dir match with it and remove it.
+ cd $modules_dir + rm -rf $modules_dir_name + fi + ;; + esac +done --The script, after this patch is applied, still contains the old script's for-loop at the end of the "new" prune-kernel script.
Amazing! now it needs some explanation how I did...you probably want that ..here are the steps.... 1)fetch that prune-kernel file from repos , which contains Bruce's code in it. 2) get inot it by editior, remove all except first two lines i.e bash interpreter and PSDX . 3)Save and commit it locally. 4) Write my own code 5) save it and commit it locally. 6) go one level up use checkpatch to see anything bad creeps in 7) Fixed the damn things if it reports. 8) create the patch 9) test it 10) Send it. Now, how the heck , that for loop is getting staying there is a mystry to me!! Look like that is ruin all the work. irk...
Nack. -- ~Randy
Attachment:
signature.asc
Description: PGP signature
