RE: possible missing error handling in hidraw

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> From: linux-input-owner@xxxxxxxxxxxxxxx 
> [mailto:linux-input-owner@xxxxxxxxxxxxxxx] On Behalf Of Jiri Kosina

> -void hidraw_report_event(struct hid_device *hid, u8 *data, int len)
> +int hidraw_report_event(struct hid_device *hid, u8 *data, int len)
>  {
>  	struct hidraw *dev = hid->hidraw;
>  	struct hidraw_list *list;
> +	int ret = 0;
>  
>  	list_for_each_entry(list, &dev->list, node) {
> -		list->buffer[list->head].value = kmemdup(data, len,
GFP_ATOMIC);
> +		if (!(list->buffer[list->head].value = kmemdup(data,
len, GFP_ATOMIC))) {
> +			ret = -ENOMEM;
> +			break;
> +		}
>  		list->buffer[list->head].len = len;
>  		list->head = (list->head + 1) & (HIDRAW_BUFFER_SIZE -
1);
>  		kill_fasync(&list->fasync, SIGIO, POLL_IN);
>  	}
>  
>  	wake_up_interruptible(&dev->wait);
> +	return ret;
>  }
> 

What happens if there is more than 1 element in the list and kmemdup
fails
halfway through the list?  Will the allocated memory leak the next time
hirdaw_report_event() is called?

James


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