On 09.07.2018 14:06, Dan Carpenter wrote:
This code is problematic because we're supposed to be writing an int but
we instead write to only the high 16 bits. This doesn't work on big
endian systems, and there is a potential that the bottom 16 bits are
used without being initialized.
Hi Dan,
Thanks for the patch.
Please correct me if I'm wrong, the caller of this function should mask
out the unused bits w.r.t. the channel spec ?
Indeed there may be an issue if we actually write the data to the wrong
16 bit part of the 32 bit integer.
Would be safer to check for the endianess and write the proper part of
the int ? (macros that do the magic for us - cpu_to_le etc.), or we rely
on the compiler to do it for us as it looks in your code ?
Another option is to pass the int directly and do the ugly task inside
the read_position/pressure functions, I am not sure which one looks better
Thanks,
Eugen
Fixes: 23ec2774f1cc ("iio: adc: at91-sama5d2_adc: add support for position and pressure channels")
Signed-off-by: Dan Carpenter <dan.carpenter@xxxxxxxxxx>
diff --git a/drivers/iio/adc/at91-sama5d2_adc.c b/drivers/iio/adc/at91-sama5d2_adc.c
index e02f7d1c86bc..d5ea84cf6460 100644
--- a/drivers/iio/adc/at91-sama5d2_adc.c
+++ b/drivers/iio/adc/at91-sama5d2_adc.c
@@ -1296,6 +1296,7 @@ static int at91_adc_read_info_raw(struct iio_dev *indio_dev,
{
struct at91_adc_state *st = iio_priv(indio_dev);
u32 cor = 0;
+ u16 tmp_val;
int ret;
/*
@@ -1309,7 +1310,8 @@ static int at91_adc_read_info_raw(struct iio_dev *indio_dev,
mutex_lock(&st->lock);
ret = at91_adc_read_position(st, chan->channel,
- (u16 *)val);
+ &tmp_val);
+ *val = tmp_val;
mutex_unlock(&st->lock);
iio_device_release_direct_mode(indio_dev);
@@ -1322,7 +1324,8 @@ static int at91_adc_read_info_raw(struct iio_dev *indio_dev,
mutex_lock(&st->lock);
ret = at91_adc_read_pressure(st, chan->channel,
- (u16 *)val);
+ &tmp_val);
+ *val = tmp_val;
mutex_unlock(&st->lock);
iio_device_release_direct_mode(indio_dev);
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