On Mon, Dec 29, 2014 at 11:29:21AM +0200, Vlad Dogaru wrote:
> Having two or more channels with the same positive scan_index field
> makes no sense. Prevent this situation by failing to register a device
> if two scan indexes are identical.
Please drop this one as well, I've just sent a v5. This just isn't my
day :)
> Signed-off-by: Vlad Dogaru <vlad.dogaru@xxxxxxxxx>
> ---
> Changes since v3:
> - only check for duplicates if device supports buffering.
> Changes since v2:
> - rebase to latest togreg branch.
> Changes since v1:
> - remove redundant check for scan_index < 0 in the inner loop.
>
> drivers/iio/industrialio-core.c | 24 ++++++++++++++++++++++++
> 1 file changed, 24 insertions(+)
>
> diff --git a/drivers/iio/industrialio-core.c b/drivers/iio/industrialio-core.c
> index ee442ee..dad6163 100644
> --- a/drivers/iio/industrialio-core.c
> +++ b/drivers/iio/industrialio-core.c
> @@ -1135,6 +1135,26 @@ static const struct file_operations iio_buffer_fileops = {
> .compat_ioctl = iio_ioctl,
> };
>
> +static int iio_check_unique_scan_index(struct iio_dev *indio_dev)
> +{
> + int i, j;
> + const struct iio_chan_spec *channels = indio_dev->channels;
> +
> + for (i = 0; i < indio_dev->num_channels - 1; i++) {
> + if (channels[i].scan_index < 0)
> + continue;
> + for (j = i + 1; j < indio_dev->num_channels; j++)
> + if (channels[i].scan_index == channels[j].scan_index) {
> + dev_err(&indio_dev->dev,
> + "Duplicate scan index %d\n",
> + channels[i].scan_index);
> + return -EINVAL;
> + }
> + }
> +
> + return 0;
> +}
> +
> static const struct iio_buffer_setup_ops noop_ring_setup_ops;
>
> /**
> @@ -1149,6 +1169,10 @@ int iio_device_register(struct iio_dev *indio_dev)
> if (!indio_dev->dev.of_node && indio_dev->dev.parent)
> indio_dev->dev.of_node = indio_dev->dev.parent->of_node;
>
> + ret = iio_check_unique_scan_index(indio_dev);
> + if (ret < 0)
> + return ret;
> +
> /* configure elements for the chrdev */
> indio_dev->dev.devt = MKDEV(MAJOR(iio_devt), indio_dev->id);
>
> --
> 1.9.1
>
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