Re: [patch v3 2/3] block: hold queue if flush is running for non-queueable flush drive

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Hello,

On Fri, May 06, 2011 at 12:32:05PM +0800, Shaohua Li wrote:
> > - This is much more minor but if block layer already knows flushes are
> >   non-queueable, it might be a good idea to hold dispatching of
> >   flushes if other requests are already in progress.  It will only
> >   save dispatch/requeue overhead which might not matter at all, so
> >   this has pretty good chance of not being worth of the added
> >   complexity tho.
>
> I did some experiment to hold flush too, but no obvious performance
> difference. It doesn't make more flush requests merge. Avoiding
> unnecessary requeue is a gain for fast devices, but my test doesn't
> show.

I see.  Thanks for testing.

> Subject: block: hold queue if flush is running for non-queueable flush drive
> 
> Commit 53d63e6b0dfb9(block: make the flush insertion use the tail of
> the dispatch list) causes about 20% regression running a sysbench fileio
> workload. Let's consider the following scenario:
> - flush1 is dispatched with write1 in the elevator.
> - Driver dispatches write1 and requeues it.
> - flush2 is issued and appended to dispatch queue after the requeued write1. 
>   As write1 has been requeued flush2 can't be put in front of it.
> - When flush1 finishes, the driver has to process write1 before flush2 even
>   though there's no fundamental reason flush2 can't be processed first and,
>   when two flushes are issued back-to-back without intervening writes, the
>   second one essentially becomes noop.
> Without the commit, flush2 is inserted before write1, so the issue is hiden.
> But the commit itself makes sense, because flush request isn't a preempt
> request, there is no reason to add it to queue head.
> 
> The regression is exposed in a SATA device. In SATA, flush requests are
> non-queueable. When flush request is running, normal read/write requests
> can't run. If block layer dispatches such request, driver can't handle it
> and requeue it. Tejun suggested we can hold the queue when flush is running.
> This can avoid unnecessary requeue.
> 
> And also this can improve performance and solve the regression. In above
> scenario, when flush1 is running, queue is hold, so write1 isn't dispatched.
> flush2 will be the only request in the queue. After flush1 is finished, flush2
> will be dispatched soon. Since there is no write between flush1 and flush2,
> flush2 essentially becomes noop.
> 
> Signed-off-by: Shaohua Li <shaohua.li@xxxxxxxxx>
> Acked-by: Tejun Heo <tj@xxxxxxxxxx>

Jens, can you please queue this for the next merge window?

Thanks.

-- 
tejun
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