Re: "ahci: drop intx manipulation on msi enable" breaks ULI M1575

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Michael Ellerman wrote:
On Wed, 2009-04-08 at 23:23 -0500, Kumar Gala wrote:
On Apr 8, 2009, at 6:53 PM, Michael Ellerman wrote:

On Wed, 2009-04-08 at 17:15 -0500, Timur Tabi wrote:
On Wed, Apr 8, 2009 at 4:31 PM, Tejun Heo <tj@xxxxxxxxxx> wrote:
Hmmm... for now,
I think it would be best to revert the original change. Jeff, can you
please do that?
Actually, give me a few days before you do that.  A colleague gave me
some suggestions to debug this.
What device did you say it was? A "ULI M1575" ?

Is that this one?

DECLARE_PCI_FIXUP_HEADER(PCI_VENDOR_ID_AL, 0x1575, hpcd_quirk_uli1575);

static void __devinit hpcd_quirk_uli1575(struct pci_dev *dev)
{
       u32 temp32;

       if (!machine_is(mpc86xx_hpcd))
               return;

       /* Disable INTx */
       pci_read_config_dword(dev, 0x48, &temp32);
       pci_write_config_dword(dev, 0x48, (temp32 | 1<<26));
..
It is the odd thing is the board he's running on is a mpc86xx_hpcd so he shouldn't be hitting the code that actually disables INTx.

Sorry Kumar that's not parsing :)

He is running an mpc86xx_hpcd, so he _should_ be hitting the code that
disables INTX?

The reversed logic of the PCI bit itself also makes for confusing discusion. In an attempt to be helpful, here is a restatement of what is happening:

1) Old 'ahci' used to clear PCI_COMMAND_INTX_DISABLE, thus ensuring INTX interrupts are enabled... if and only if MSI is unavailable.

2) Current 'ahci' no longer does this

3) As a result, Timur's 'ahci' is no longer receiving interrupts. Presumably this means that BOTH of the following conditions are true

	a) INTX is disabled
	b) MSI is not available

Today I am thinking we should either revert the libata commit (a5bfc4714b3f01365aef89a92673f2ceb1ccf246), or poke PCI to twiddle INTX for us at pci_enable_device() time, perhaps.

I lean towards the former, but maybe the platform folks prefer a third solution?

	Jeff




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