Hello, I wrote:
HPT36x chip don't seem to have the channel enable bits, so prevent the IDE core
from checking them...
Signed-off-by: Sergei Shtylyov <sshtylyov@xxxxxxxxxxxxx>
Index: linux-2.6/drivers/ide/pci/hpt366.c
===================================================================
--- linux-2.6.orig/drivers/ide/pci/hpt366.c
+++ linux-2.6/drivers/ide/pci/hpt366.c
@@ -1,5 +1,5 @@
/*
- * linux/drivers/ide/pci/hpt366.c Version 1.02 Apr 18, 2007
+ * linux/drivers/ide/pci/hpt366.c Version 1.03 May 4, 2007
*
* Copyright (C) 1999-2003 Andre Hedrick <andre@xxxxxxxxxxxxx>
* Portions Copyright (C) 2001 Sun Microsystems, Inc.
@@ -1527,7 +1527,12 @@ static int __devinit init_setup_hpt366(s
if (rev > 2)
goto init_single;
+ /*
+ * HPT36x chips are single channel and
+ * do not seem to have the channel enable bit...
+ */
Actually it does, but the bit is different. :-/
d->channels = 1;
+ d->enablebits[0].reg = 0;
Linas, Andries, Michal, cound you try this instead:
d->enablebits[0].mask = d->enablebits[0].val = 0x10;
if ((dev2 = pci_get_slot(dev->bus, dev->devfn + 1)) != NULL) {
u8 pin1 = 0, pin2 = 0;
MBR, Sergei
-
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