Re: [RFC 02/32] Kconfig: introduce HAS_IOPORT option and select it as necessary

[Geert Uytterhoeven <geert@xxxxxxxxxxxxxx>]

Hi Niklas,

On Mon, Dec 27, 2021 at 5:44 PM Niklas Schnelle <schnelle@xxxxxxxxxxxxx> wrote:
> We introduce a new HAS_IOPORT Kconfig option to gate support for
> I/O port access. In a future patch HAS_IOPORT=n will disable compilation
> of the I/O accessor functions inb()/outb() and friends on architectures
> which can not meaningfully support legacy I/O spaces. On these platforms
> inb()/outb() etc are currently just stubs in asm-generic/io.h which when
> called will cause a NULL pointer access which some compilers actually
> detect and warn about.
>
> The dependencies on HAS_IOPORT in drivers as well as ifdefs for
> HAS_IOPORT specific sections will be added in subsequent patches on
> a per subsystem basis. Then a final patch will ifdef the I/O access
> functions on HAS_IOPORT thus turning any use not gated by HAS_IOPORT
> into a compile-time warning.
>
> Link: https://lore.kernel.org/lkml/CAHk-=wg80je=K7madF4e7WrRNp37e3qh6y10Svhdc7O8SZ_-8g@xxxxxxxxxxxxxx/
> Co-developed-by: Arnd Bergmann <arnd@xxxxxxxxxx>
> Signed-off-by: Arnd Bergmann <arnd@xxxxxxxxxx>
> Signed-off-by: Niklas Schnelle <schnelle@xxxxxxxxxxxxx>

Thanks for your patch!

> --- a/arch/m68k/Kconfig
> +++ b/arch/m68k/Kconfig
> @@ -16,6 +16,7 @@ config M68K
>         select GENERIC_CPU_DEVICES
>         select GENERIC_IOMAP
>         select GENERIC_IRQ_SHOW
> +       select HAS_IOPORT
>         select HAVE_AOUT if MMU
>         select HAVE_ASM_MODVERSIONS
>         select HAVE_DEBUG_BUGVERBOSE

This looks way too broad to me: most m68k platform do not have I/O
port access support.

My gut feeling says:

    select HAS_IOPORT if PCI || ISA

but that might miss some intricate details...

Gr{oetje,eeting}s,

                        Geert

--
Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- geert@xxxxxxxxxxxxxx

In personal conversations with technical people, I call myself a hacker. But
when I'm talking to journalists I just say "programmer" or something like that.
                                -- Linus Torvalds