> +static int ocores_poll_wait(struct ocores_i2c *i2c) > +{ > + u8 mask; > + int err; > + > + if (i2c->state == STATE_DONE || i2c->state == STATE_ERROR) { > + /* transfer is over */ > + mask = OCI2C_STAT_BUSY; > + } else { > + /* on going transfer */ > + mask = OCI2C_STAT_TIP; > + udelay((8 * 1000) / i2c->bus_clock_khz); > + } > + > + /* > + * once we are here we expect to get the expected result immediately > + * so if after 1ms we timeout then something is broken. > + */ > + err = ocores_wait(i2c, OCI2C_STATUS, mask, 0, msecs_to_jiffies(1)); Hi Federico I did some timing tests for this. On my box, we request a udelay of 80uS. The kernel actually delays for about 79uS. We then spin in ocores_wait() for an additional 10-11uS, which is 3 to 4 iterations. There are actually 9 bits on the wire, not 8, since there is an ACK/NACK bit after the actual data transfer. So i changed the delay to (9 * 1000) / i2c->bus_clock_khz. That resulted in ocores_wait() mostly not looping at all. But for reading an 4K AT24 EEPROM, it increased the read time by 10ms, from 424ms to 434ms. So we should probably keep with 8. Tested-by: Andrew Lunn <andrew@xxxxxxx> Andrew