On Tue, Aug 15, 2023 at 03:07:50PM +0200, Linus Walleij wrote: > On Tue, Aug 15, 2023 at 2:57 PM Andy Shevchenko > <andriy.shevchenko@xxxxxxxxxxxxxxx> wrote: > > On Tue, Aug 15, 2023 at 01:40:22PM +0200, Linus Walleij wrote: > > > On Tue, Aug 15, 2023 at 11:50 AM Andy Shevchenko > > > <andriy.shevchenko@xxxxxxxxxxxxxxx> wrote: > > > > On Fri, Aug 11, 2023 at 09:30:34PM +0200, Bartosz Golaszewski wrote: ... > > > > > + module_put(desc->gdev->owner); > > > > > + gpio_device_put(desc->gdev); > > > > > > > > So, if gdev can be NULL, you will get an Oops with new code. > > > > > > I read it such that gdev->chip can be NULL, but not gdev, > > > and desc->gdev->owner is fine to reference? > > > > Basically the Q is > > "if desc is non-NULL, does it guarantee that gdev is non-NULL either?" > > gdev->desc is assigned in one single spot, which is in > gpiochip_add_data_with_key(): > > for (i = 0; i < gc->ngpio; i++) > gdev->descs[i].gdev = gdev; > > It is never assigned anywhere else, so I guess yes. > > We may also ask if it is ever invalid (i.e. if desc->gdev can point to > junk). > > A gdev turns to junk when its reference count goes down to zero > and gpiodev_release() is called effectively calling kfree() on the > struct gpio_device *. > > But that can only happen as a result of module_put() getting > called, pulling the references down to zero. Which is what we > are discussing. The line after module_put(), desc->gdev > *could* be NULL. Yes. > But then we just call gpio_device_put(desc->gdev) which is > just a call to device_put(), which is NULL-tolerant. But gpio_device_put() does not NULL tolerant. So, oops in this line then. -- With Best Regards, Andy Shevchenko