+static int tps6594_get_rdev_by_name(const char *regulator_name,
+ struct regulator_dev *rdevbucktbl[BUCK_NB],
+ struct regulator_dev *rdevldotbl[LDO_NB],
+ struct regulator_dev *dev)
+{
+ int i;
+
+ for (i = 0; i <= BUCK_NB; i++) {
+ if (strcmp(regulator_name, buck_regs[i].name) == 0) {
+ dev = rdevbucktbl[i];
+ return 0;
+ }
+ }
+
+ for (i = 0; i < ARRAY_SIZE(ldo_regs); i++) {
+ if (strcmp(regulator_name, ldo_regs[i].name) == 0) {
+ dev = rdevldotbl[i];
+ return 0;
+ }
+ }
+ return -EINVAL;
+}
+ for (i = 0; i < ARRAY_SIZE(tps6594_regulator_irq_types); ++i) {
+ irq_type = &tps6594_regulator_irq_types[i];
+
+ irq = platform_get_irq_byname(pdev, irq_type->irq_name);
+ if (irq < 0)
+ return -EINVAL;
+
+ irq_data[i].dev = tps->dev;
+ irq_data[i].type = irq_type;
+
+ tps6594_get_rdev_by_name(irq_type->regulator_name, rdevbucktbl,
+ rdevldotbl, rdev);
This would be simpler and you wouldn't need this lookup function if the
regulator descriptions included their IRQ names, then you could just
request the interrupts while registering the regulators.
I changed the code to follow your recommendations then now in case of a
multiphase buck, only one set of interrupt is requested.
ex: multiphase buck1234 single buck5
cat /proc/interrupts:
563: 0 0 tps6594-0-0x4c 0 Edge buck1_ov
564: 0 0 tps6594-0-0x4c 1 Edge buck1_uv
565: 0 0 tps6594-0-0x4c 2 Edge buck1_sc
566: 0 0 tps6594-0-0x4c 3 Edge buck1_ilim
579: 0 0 tps6594-0-0x4c 16 Edge buck5_ov
580: 0 0 tps6594-0-0x4c 17 Edge buck5_uv
581: 0 0 tps6594-0-0x4c 18 Edge buck5_sc
582: 0 0 tps6594-0-0x4c 19 Edge buck5_ilim
buck2, buck3, buck4 are not associated to a regulator device because
buck1 registers control all the multiphase bucks (only one logic
regulator). Consequently the mapping for the associated interrupts does
not occur.
I'm not sure it's the right option.
Do you suggest to keep it like that for multiphase?
Is it better to request all the interrupts anyway and map it to the same
rdev?
+ error = devm_request_threaded_irq(tps->dev, irq, NULL,
+ tps6594_regulator_irq_handler,
+ IRQF_ONESHOT,
+ irq_type->irq_name,
+ &irq_data[i]);
+ if (error) {
+ dev_err(tps->dev, "failed to request %s IRQ %d: %d\n",
+ irq_type->irq_name, irq, error);
+ return error;
+ }
This leaks all previously requested interrupts.
I'm not sure to understand this sentence correctly. You mean all the
interrupts already requested are still allocated after the error occurs?
