On Mon, Oct 19, 2020 at 02:17:49PM +0200, Bartosz Golaszewski wrote: > On Fri, Oct 16, 2020 at 3:38 PM Bartosz Golaszewski <brgl@xxxxxxxx> wrote: > > > > On Fri, Oct 16, 2020 at 12:29 PM Helmut Grohne <helmut.grohne@xxxxxxxxxx> wrote: > > > > > > > [snip] > > > > > > +chip::chip(const ::std::weak_ptr<::gpiod_chip>& chip_ptr) > > > > + : _m_chip(chip_ptr) > > > > +{ > > > > + > > > > +} > > > > + > > > > > > I think what happens here is that you upgrade a weak_ptr to a > > > shared_ptr. Wouldn't it be more natural to request a > > > > > > ::std::shared_ptr<::gpiod_chip> && > > > > > > here and thus make the ownership-taking more explicit? It would be done > > > on the caller-side and thus be more transparent. Stuffing weak_ptrs > > > should continue to work. > > > > > > > Sure, sounds good. > > > > After a second look - I'm not sure if this is actually better. By > taking weak_ptr reference as argument we benefit from implicit > conversion to shared_ptr via shared_ptr's constructor taking weak_ptr > as argument. What you propose would require us to always instantiate a > shared_ptr in the argument list when calling the chip's constructor > and makes code uglier in the end IMO. On a second look, the use of an rvalue reference is suboptimal indeed. The idea behind my change was this: Since chip stores a shared_ptr, it can as well consume one. Instead of what I proposed, it should simply take it by value (not rvalue): ::std::shared_ptr<::gpiod_chip> An existing shared_ptr can be moved into the constructor and then moved into the member variable. Doing so allows passing a shared_ptr around without touching reference counts (which are prone to cache line bouncing). When passing it by value, the implicit conversion from weak_ptr should work again. Thus the caller would increase the reference count and the chip would merely gain ownership of the shared_ptr and move it around. For reference, see Scott Myers' Effective Modern C++ "Item 41: Consider pass by value for copyable parameters that are cheap to move and always copied." So yeah, it doesn't work the way I wrote initially, because I added the rvalue reference. Helmut