Each iteration of for_each_child_of_node and for_each_available_child_of_node puts the previous node, but in the case of a return from the middle of the loop, there is no put, thus causing a memory leak. Hence add an of_node_put before the return in two places. Issue found with Coccinelle. Signed-off-by: Nishka Dasgupta <nishkadg.linux@xxxxxxxxx> --- drivers/pinctrl/stm32/pinctrl-stm32.c | 5 ++++- 1 file changed, 4 insertions(+), 1 deletion(-) diff --git a/drivers/pinctrl/stm32/pinctrl-stm32.c b/drivers/pinctrl/stm32/pinctrl-stm32.c index b453aed1bbeb..2d5e0435af0a 100644 --- a/drivers/pinctrl/stm32/pinctrl-stm32.c +++ b/drivers/pinctrl/stm32/pinctrl-stm32.c @@ -615,6 +615,7 @@ static int stm32_pctrl_dt_node_to_map(struct pinctrl_dev *pctldev, &reserved_maps, num_maps); if (ret < 0) { pinctrl_utils_free_map(pctldev, *map, *num_maps); + of_node_put(np); return ret; } } @@ -1468,8 +1469,10 @@ int stm32_pctl_probe(struct platform_device *pdev) for_each_available_child_of_node(np, child) { if (of_property_read_bool(child, "gpio-controller")) { ret = stm32_gpiolib_register_bank(pctl, child); - if (ret) + if (ret) { + of_node_put(child); return ret; + } pctl->nbanks++; } -- 2.19.1