-------- Original Message --------
Subject: Re: [RFC] odd thing in btrfs_file_aio_write()
From: Al Viro <viro@xxxxxxxxxxxxxxxxxx>
To: Qu Wenruo <quwenruo@xxxxxxxxxxxxxx>
Date: 2014年04月14日 13:08
On Mon, Apr 14, 2014 at 11:36:53AM +0800, Qu Wenruo wrote:
IOW, is that if (start_pos > i_size_read(inode)) { in there correct
these days? And what'll happen if we hit e.g. an unmapped page in the
middle of the data being written? That will result in short write, but
will it truncate what's left of that dummy range?
I'm very sorry for my poor that I could not understand the question well.
Would you please explain what does the "unmapped page" means?
Did you mean two noncontinuous iovecs?
If you did mean that, it seems that I should expand the end_pos to
the end of the iovec...
I mean that the very first (and only) iovec can very well span an area
that has been munmapped():
char *buf = (char *)mmap(NULL, 65536, PROT_READ, MAP_ANON, -1, 0);
memset(buf, 'A', 65536);
munmap(buf + 4096, 4096);
write(fd, buf, 65536);
or
char *buf = (char *)mmap(NULL, 65536, PROT_READ, MAP_ANON, -1, 0);
struct iovec iv = {buf, 65536};
memset(buf, 'A', 65536);
munmap(buf + 4096, 4096);
writev(fd, &iv, 1);
will end up writing 4Kb of data (filled with 'A') and return 4096. That's
how short writes happen...
Since the inode size on disk is updated only when the write finished, so
even the hole punched is larger
than the data written, it will be OK since the inode size on disk is not
expended to 64K.
Although short writes is OK, when two noncontinuous iovecs is passed,
there is still empty gap,
so I still needs to fix the code.
Thanks,
Qu
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