On Wed 16-02-11 06:52:55, Tetsuo Handa wrote:
> Jan Kara wrote:
> > Ext3 looks innocent here. That is a standard call path for open(..,
> > O_TRUNC). But apparently something broke in SLUB allocator. Adding proper
> > list to CC...
>
> Thanks.
>
> Both fs/jbd/transaction.c and fs/jbd2/transaction.c provide start_this_handle()
> and I don't know which one was called.
>
> But
>
> if (!journal->j_running_transaction) {
> new_transaction = kzalloc(sizeof(*new_transaction),
> GFP_NOFS|__GFP_NOFAIL);
> if (!new_transaction) {
> ret = -ENOMEM;
> goto out;
> }
> }
>
> does kzalloc(GFP_NOFS|__GFP_NOFAIL) causes /proc/$PID/status to show
>
> State: D (disk sleep)
It could. State D does not mean "disk sleep" but "uninterruptible sleep".
Lots of sleeps in kernel are in D state - for example waiting for all mutex
locks, waiting for IO, etc. But looking at the trace again, you're probably
right that we are actually waiting somewhere in start_this_handle() (in
fs/jbd/transaction.c) and __slab_alloc() is just some relict on stack. You
can verify this by looking at disassembly of start_this_handle() in your
kernel and finding out where offset 0x22d is in the function...
But in this case - does the process (sh) eventually resume or is it stuck
forever?
Honza
--
Jan Kara <jack@xxxxxxx>
SUSE Labs, CR
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