On Sun, Jan 28, 2024 at 12:56:32PM -0800, Kuniyuki Iwashima wrote: > From: Kent Overstreet <kent.overstreet@xxxxxxxxx> > Date: Sun, 28 Jan 2024 14:38:02 -0500 > > On Sun, Jan 28, 2024 at 12:28:38AM -0800, Kuniyuki Iwashima wrote: > > > From: Kent Overstreet <kent.overstreet@xxxxxxxxx> > > > Date: Fri, 26 Jan 2024 21:08:31 -0500 > > > > Kill > > > > - unix_state_lock_nested > > > > - _nested usage for net->unx.table.locks[]. > > > > > > > > replace both with lock_set_cmp_fn_ptr_order(&u->lock). > > > > > > > > The lock ordering in sk_diag_dump_icons() looks suspicious; this may > > > > turn up a real issue. > > > > > > Yes, you cannot use lock_cmp_fn() for unix_state_lock_nested(). > > > > > > The lock order in sk_diag_dump_icons() is > > > > > > listening socket -> child socket in the listener's queue > > > > > > , and the inverse order never happens. ptr comparison does not make > > > sense in this case, and lockdep will complain about false positive. > > > > Is that a real lock ordering? Is this parent -> child relationship well > > defined? > > > > If it is, we should be able to write a lock_cmp_fn for it, as long as > > it's not some handwavy "this will never happen but _nested won't check > > for it" like I saw elsewhere in the net code... :) > > The problem would be there's no handy way to detect the relationship > except for iterating the queue again. > > ---8<--- > static int unix_state_lock_cmp_fn(const struct lockdep_map *_a, > const struct lockdep_map *_b) > { > const struct unix_sock *a = container_of(_a, struct unix_sock, lock.dep_map); > const struct unix_sock *b = container_of(_b, struct unix_sock, lock.dep_map); > > if (a->sk.sk_state == TCP_LISTEN && b->sk.sk_state == TCP_ESTABLISHED) { > /* check if b is a's cihld */ > } > > /* otherwise, ptr comparison here. */ > } > ---8<--- > > > This can be resolved by a patch like this, which is in my local tree > for another series. > > So, after posting the series, I can revisit this and write lock_cmp_fn > for u->lock. Sounds good! Please CC me when you do.