From: "GONG, Ruiqi" <gongruiqi1@xxxxxxxxxx> If the modified paragraph is referring to the idmapping mentioned in the previous paragraph (i.e. `u0:k10000:r10000`), then it is `u0` that the upper idmapset starts with, not `u1000`. Fix this error and rephrase this paragraph a bit to make this reference more explicit. Reported-by: Wang Lei <wanglei249@xxxxxxxxxx> Signed-off-by: GONG, Ruiqi <gongruiqi1@xxxxxxxxxx> --- Documentation/filesystems/idmappings.rst | 7 ++++--- 1 file changed, 4 insertions(+), 3 deletions(-) diff --git a/Documentation/filesystems/idmappings.rst b/Documentation/filesystems/idmappings.rst index f3d168c9f0b9..d095c5838f94 100644 --- a/Documentation/filesystems/idmappings.rst +++ b/Documentation/filesystems/idmappings.rst @@ -146,9 +146,10 @@ For the rest of this document we will prefix all userspace ids with ``u`` and all kernel ids with ``k``. Ranges of idmappings will be prefixed with ``r``. So an idmapping will be written as ``u0:k10000:r10000``. -For example, the id ``u1000`` is an id in the upper idmapset or "userspace -idmapset" starting with ``u1000``. And it is mapped to ``k11000`` which is a -kernel id in the lower idmapset or "kernel idmapset" starting with ``k10000``. +For example, within this idmapping, the id ``u1000`` is an id in the upper +idmapset or "userspace idmapset" starting with ``u0``. And it is mapped to +``k11000`` which is a kernel id in the lower idmapset or "kernel idmapset" +starting with ``k10000``. A kernel id is always created by an idmapping. Such idmappings are associated with user namespaces. Since we mainly care about how idmappings work we're not -- 2.25.1
