On 3/23/22 1:04 AM, Matthew Wilcox wrote: > On Mon, Mar 21, 2022 at 03:30:52PM +0000, David Howells wrote: >> Matthew Wilcox <willy@xxxxxxxxxxxxx> wrote: >> >>> Absolutely; just use xa_lock() to protect both setting & testing the >>> flag. >> >> How should Jeffle deal with xarray dropping the lock internally in order to do >> an allocation and then taking it again (actually in patch 5)? > > There are a number of ways to handle this. I'll outline two; others > are surely possible. Thanks. > > option 1: > > add side: > > xa_lock(); > if (!DEAD) > xa_store(GFP_KERNEL); > if (DEAD) > xa_erase(); > xa_unlock(); > > destroy side: > > xa_lock(); > set DEAD; > xa_for_each() > xa_erase(); > xa_unlock(); > > That has the problem (?) that it might be temporarily possible to see > a newly-added entry in a DEAD array. I think this problem doesn't matter in our scenario. > > If that is a problem, you can use xa_reserve() on the add side, followed > by overwriting it or removing it, depending on the state of the DEAD flag. Right. Then even the normal path (when memory allocation succeeds) needs to call xa_reserve() once. > > If you really want to, you can decompose the add side so that you always > check the DEAD flag before doing the store, ie: > > do { > xas_lock(); > if (DEAD) > xas_set_error(-EINVAL); > else > xas_store(); > xas_unlock(); > } while (xas_nomem(GFP_KERNEL)); This way is more cleaner from the locking semantics, with the cost of code duplication. However, after decomposing the __xa_alloc(), we can also reuse the xas when setting CACHEFILES_REQ_NEW mark. ``` + xa_lock(xa); + ret = __xa_alloc(xa, &id, req, xa_limit_32b, GFP_KERNEL); + if (!ret) + __xa_set_mark(xa, id, CACHEFILES_REQ_NEW); + xa_unlock(xa); ``` So far personally I prefer the decomposing way in our scenario. -- Thanks, Jeffle