Re: [PATCH v2 1/5] exec: Only compute current once in flush_old_exec

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On 3/8/20 10:35 PM, Eric W. Biederman wrote:
> 
> Make it clear that current only needs to be computed once in
> flush_old_exec.  This may have some efficiency improvements and it
> makes the code easier to change.
> 
> Signed-off-by: "Eric W. Biederman" <ebiederm@xxxxxxxxxxxx>
> ---
>  fs/exec.c | 9 +++++----
>  1 file changed, 5 insertions(+), 4 deletions(-)
> 
> diff --git a/fs/exec.c b/fs/exec.c
> index db17be51b112..c3f34791f2f0 100644
> --- a/fs/exec.c
> +++ b/fs/exec.c
> @@ -1260,13 +1260,14 @@ void __set_task_comm(struct task_struct *tsk, const char *buf, bool exec)
>   */
>  int flush_old_exec(struct linux_binprm * bprm)
>  {
> +	struct task_struct *me = current;
>  	int retval;
>  
>  	/*
>  	 * Make sure we have a private signal table and that
>  	 * we are unassociated from the previous thread group.
>  	 */
> -	retval = de_thread(current);
> +	retval = de_thread(me);
>  	if (retval)
>  		goto out;
>  
> @@ -1294,10 +1295,10 @@ int flush_old_exec(struct linux_binprm * bprm)
>  	bprm->mm = NULL;
>  
>  	set_fs(USER_DS);
> -	current->flags &= ~(PF_RANDOMIZE | PF_FORKNOEXEC | PF_KTHREAD |
> +	me->flags &= ~(PF_RANDOMIZE | PF_FORKNOEXEC | PF_KTHREAD |
>  					PF_NOFREEZE | PF_NO_SETAFFINITY);

I wonder if this line should be aligned with the previous?


Bernd.



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