Waiman reported that on large systems with a large amount of interrupts the
readout of /proc/stat takes a long time to sum up the interrupt
statistics. In principle this is not a problem. but for unknown reasons
some enterprise quality software reads /proc/stat with a high frequency.
The reason for this is that interrupt statistics are accounted per cpu. So
the /proc/stat logic has to sum up the interrupt stats for each interrupt.
The interrupt core provides now a per interrupt summary counter which can
be used to avoid the summation loops completely except for interrupts
marked PER_CPU which are only a small fraction of the interrupt space if at
all.
Another simplification is to iterate only over the active interrupts and
skip the potentially large gaps in the interrupt number space and just
print zeros for the gaps without going into the interrupt core in the first
place.
Reported-by: Waiman Long <longman@xxxxxxxxxx>
Signed-off-by: Thomas Gleixner <tglx@xxxxxxxxxxxxx>
---
fs/proc/stat.c | 28 +++++++++++++++++++++++++---
1 file changed, 25 insertions(+), 3 deletions(-)
--- a/fs/proc/stat.c
+++ b/fs/proc/stat.c
@@ -79,6 +79,30 @@ static u64 get_iowait_time(int cpu)
#endif
+static void show_irq_gap(struct seq_file *p, int gap)
+{
+ static const char zeros[] = " 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0";
+
+ while (gap > 0) {
+ int inc = min_t(int, gap, ARRAY_SIZE(zeros) / 2);
+
+ seq_write(p, zeros, 2 * inc);
+ gap -= inc;
+ }
+}
+
+static void show_all_irqs(struct seq_file *p)
+{
+ int i, next = 0;
+
+ for_each_active_irq(i) {
+ show_irq_gap(p, i - next);
+ seq_put_decimal_ull(p, " ", kstat_irqs_usr(i));
+ next = i + 1;
+ }
+ show_irq_gap(p, nr_irqs - next);
+}
+
static int show_stat(struct seq_file *p, void *v)
{
int i, j;
@@ -156,9 +180,7 @@ static int show_stat(struct seq_file *p,
}
seq_put_decimal_ull(p, "intr ", (unsigned long long)sum);
- /* sum again ? it could be updated? */
- for_each_irq_nr(j)
- seq_put_decimal_ull(p, " ", kstat_irqs_usr(j));
+ show_all_irqs(p);
seq_printf(p,
"\nctxt %llu\n"
