Re: [fuse-devel] fuse: when are release requests queued?

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On 05/31/2017 12:41 PM, Nikolaus Rath wrote:

On May 31 2017, Maxim Patlasov <mpatlasov@xxxxxxxxxxxxx> wrote:
On 05/31/2017 12:19 PM, Nikolaus Rath wrote:

On May 31 2017, Maxim Patlasov <mpatlasov@xxxxxxxxxxxxx> wrote:
Can someone tell me at which point the fuse kernel module will send a
RELEASE request to userspace?
Anytime after fuse_release(). It only puts request to background
queue. Later, the request will be transferred to pending queue. And
later, the userspace will fetch it by fuse_dev_do_read().

Is it possible that this is delayed until
after the close() syscall for the last fd has returned and userspace has
submitted a different fuse request for the same fs?
I think it's possible. See how flush_bg_queue() do nothing if
fc->active_background > fc->max_background.
Thanks Maxim! Not sure what I'd do with these issues without you :-).


Is there a way to deliberate trigger this behavior for debugging? For
example, is there a kernel equivalent of sleep(1) that I could put into
fuse_release()?
schedule_timeout_interruptible(HZ).
Hmm. I made the following change in linux 4.10:

diff --git a/fs/fuse/file.c b/fs/fuse/file.c
index 2401c5..3568a8 100644
--- a/fs/fuse/file.c
+++ b/fs/fuse/file.c
@@ -252,6 +252,9 @@ void fuse_release_common(struct file *file, int opcode)
          if (unlikely(!ff))
                  return;
   +        // Wait a little to force race condition in userspace
+        schedule_timeout_interruptible(1);
+
          req = ff->reserved_req;
          fuse_prepare_release(ff, file->f_flags, opcode);
But when doing e.g. "echo test > newfile", the RELEASE request still
comes right away (judging from the libfuse debugging output).

Do I need to do something else?
Try HZ*10 instead of 1 as an argument of
schedule_timeout_interruptible.
Ok, now the RELEASE comes a lot later. But now userspace is also
blocking until RELEASE comes in.

That's exactly why I thought that adding sleep there wouldn't be very useful.


But it's better to instrument fuse
userspace to postpone processing some i/o requests. Then you'll keep
fc->active_background > fc->max_background for a while. During that
period fuse_release may succeed with FUSE_RELEASE queued, but not
passed to the userspace. Then you cat try to sneak another request --
something not involving fuse background queue.
I don't know.. why is this better? It seems a lot more complicated. I
need to generate the extra request, add some switch to tell libfuse when
to start processing again, synchronize this with sneaking in the other
request...
I thought it's better because it would trigger delayed processing of
FUSE_RELEASE: last __fput() succeeded, but fuse userspace will see
FUSE_RELEASE only later. Adding sleep to fuse_release_common would
only extend processing time of last __fput(), is that what you need?
I do not fully understand the difference you describe. What I would like
to construct is the following scenario:

1. Userspace calls close()
2. Userspace close() returns
3. Userspace calls unlink()
4. Userspace unlink() returns
5. libfuse reads UNLINK request from kernel pipe
6. libfuse reads RELEASE request from kernel pipe

What would be the simplest way to do that?

I would try to keep fc->active_background elevated somehow. For example you add sleep(1) for every incoming write request to libfuse and serialize processing them. Then you generate enough writes to achieve fc->max_background. If you call close() now, and if it really ends up in last __fput(), corresponding FUSE_RELEASE will sit in background queue for long while (as many seconds as # elements in the queue). But close() from your 2. will return much earlier because it doesn't wait for completion of FUSE_RELEASE. Hence unlink() might succeed.


Thanks!
-Nikolaus





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