On Fri, May 19, 2017 at 11:58:41AM +0100, David Howells wrote: > Christoph Hellwig <hch@xxxxxx> wrote: > > > It's not a userspace ABI, so by defintion it does not break an > > existing user program. > > That's an invalid assumption. It is a de facto userspace ABI as it has been > exposed in /usr/include/linux/uuid.h for some time. It is never passed through any kernel interface, which by defintion does not make it an ABI. And even if it was we are not going to change the ABI for a uuid_t ever. We're just changing the internal name, and stop exposing the old name which was never used in an ABI to userspace.
