On Wed, 23 May 2007 19:07:32 +0400, Evgeniy Polyakov wrote:
> On Wed, May 23, 2007 at 02:58:41PM +0200, Jörn Engel (joern@xxxxxxxxxxxxxxx) wrote:
> > On Sun, 20 May 2007 21:30:52 +0400, Evgeniy Polyakov wrote:
>
> And what if it is 33 bits? Or it is not allowed?
Not allowed. Both number and size of segments may never exceed 32bit.
> > > segsize is long, but should be u64 I think.
> >
> > It could be s32 as well.
>
> It is a matter of definition - if segment size is allowed to be more
> than 32 bits, then below transformation is not correct, otherwise
> segment size should not use additional 32bits on 64bit platform, since
> it is long.
I guess I could save 4 Bytes there.
> > I'm just a German. Forgive me if I drink lesser beverages.
>
> You should definitely change that.
Change being German? Not a bad idea, actually.
> Btw, what about this piece:
>
> int logfs_erase_segment(struct super_block *sb, u32 index)
> {
> struct logfs_super *super = LOGFS_SUPER(sb);
>
> super->s_gec++;
>
> return mtderase(sb, index << super->s_segshift, super->s_segsize);
> }
>
> index << super->s_segshift might overflow, mtderase expects loff_t
> there, since index can be arbitrary segment number, is it possible, that
> overflow really occurs?
Indeed it is. You just earned your second beer^Wvodka.
Jörn
--
The wise man seeks everything in himself; the ignorant man tries to get
everything from somebody else.
-- unknown
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