在 2022/5/25 19:29, Jan Kara 写道:
On Tue 24-05-22 21:44:31, Baokun Li wrote:
在 2022/5/24 17:30, Jan Kara 写道:
On Mon 23-05-22 21:04:16, libaokun (A) wrote:
在 2022/5/23 17:40, Jan Kara 写道:
On Sat 21-05-22 21:42:17, Baokun Li wrote:
When either of the "start + size <= ac->ac_o_ex.fe_logical" or
"start > ac->ac_o_ex.fe_logical" conditions is met, it indicates
that the fe_logical is not in the allocated range.
In this case, it should be bug_ON.
Fixes: dfe076c106f6 ("ext4: get rid of code duplication")
Signed-off-by: Baokun Li<libaokun1@xxxxxxxxxx>
I think this is actually wrong. The original condition checks whether
start + size does not overflow the used integer type. Your condition is
much stronger and I don't think it always has to be true. E.g. allocation
goal block (start variable) can be pushed to larger values by existing
preallocation or so.
Honza
I think there are two reasons for this:
First of all, the code here is as follows.
```
size = end - start;
[...]
if (start + size <= ac->ac_o_ex.fe_logical &&
start > ac->ac_o_ex.fe_logical) {
ext4_msg(ac->ac_sb, KERN_ERR,
"start %lu, size %lu, fe_logical %lu",
(unsigned long) start, (unsigned long) size,
(unsigned long) ac->ac_o_ex.fe_logical);
BUG();
}
BUG_ON(size <= 0 || size > EXT4_BLOCKS_PER_GROUP(ac->ac_sb));
```
First of all, there is no need to compare with ac_o_ex.fe_logical if it is
to determine whether there is an overflow.
Because the previous logic guarantees start < = ac_o_ex.fe_logical, and
How does it guarantee that? The logic:
if (ar->pleft && start <= ar->lleft) {
size -= ar->lleft + 1 - start;
start = ar->lleft + 1;
}
can move 'start' to further blocks...
This is not the case. According to the code of the preceding process,
ar->pleft and ar->pright are assigned values in ext4_ext_map_blocks.
ar->pleft is the first allocated block found to the left by map->m_lblk
(that is, fe_logical),
and ar->pright is the first allocated block found to the right.
ar->lleft and ar->lright are logical block numbers, so there must be
"ar->lleft < ac_o_ex.fe_logical < ar->lright".
Right, I've found that out after sending my previous email. Sorry for
confusion.
Don't be sorry. Thank you very much for your advice. It has benefited me
a lot.
Secondly, the following code flow also reflects this logic.
ext4_mb_normalize_request
>>> start + size <= ac->ac_o_ex.fe_logical
ext4_mb_regular_allocator
ext4_mb_simple_scan_group
ext4_mb_use_best_found
ext4_mb_new_preallocation
ext4_mb_new_inode_pa
ext4_mb_use_inode_pa
>>> set ac->ac_b_ex.fe_len <= 0
ext4_mb_mark_diskspace_used
>>> BUG_ON(ac->ac_b_ex.fe_len <= 0);
In ext4_mb_use_inode_pa, you have the following code.
```
start = pa->pa_pstart + (ac->ac_o_ex.fe_logical - pa->pa_lstart);
end = min(pa->pa_pstart + EXT4_C2B(sbi, pa->pa_len), start + EXT4_C2B(sbi,
ac->ac_o_ex.fe_len));
len = EXT4_NUM_B2C(sbi, end - start);
ac->ac_b_ex.fe_len = len;
```
The starting position in ext4_mb_mark_diskspace_used will be assert.
BUG_ON(ac->ac_b_ex.fe_len <= 0);
When end == start + EXT4_C2B(sbi, ac->ac_o_ex.fe_len) is used, the value of
end - start must be greater than 0.
However, when end == pa->pa_pstart + EXT4_C2B(sbi, pa->pa_len) occurs, this
bug_ON may be triggered.
When this bug_ON is triggered, that is,
ac->ac_b_ex.fe_len <= 0
end - start <= 0
end <= start
pa->pa_pstart + EXT4_C2B(sbi, pa->pa_len) <= pa->pa_pstart +
(ac->ac_o_ex.fe_logical - pa->pa_lstart)
pa->pa_len <= ac->ac_o_ex.fe_logical - pa->pa_lstart
pa->pa_lstart + pa->pa_len <= ac->ac_o_ex.fe_logical
start + size <= ac->ac_o_ex.fe_logical
So I think that "&&" here should be changed to "||".
Sorry, I still disagree. After some more code reading I agree that
ac->ac_o_ex.fe_logical is the logical block where we want allocated blocks
to be placed in the inode so logical extent of allocated blocks should include
ac->ac_o_ex.fe_logical. But I would be reluctant to make assertion you
suggest unless we make sure ac->ac_o_ex.fe_logical in unallocated (in which
case we can also remove some other code from ext4_mb_normalize_request()).
Honza
What codes are you referring to that can be deleted?
So I though the shifting of 'start' by lleft cannot happen but then I
realized that if 'start' got aligned down, it can now be lower than lleft
so the shifting is indeed needed. So all code is needed there.
Honza
Okay, thanks again!
--
With Best Regards,
Baokun Li
.
