On Wed, Apr 14, 2021 at 12:41:27AM -0700, Michael Forney wrote: > Functionally, the statement-expression is not necessary here; it > just gives a bit of type-safety to make sure the pointer really > does have a compatible type with the specified member of the struct. > > When statement expressions are not available, we can just use a > portable fallback macro that skips this member type check. > > Signed-off-by: Michael Forney <mforney@xxxxxxxxxxx> Applied, thanks. - Ted
