On Mon, Jan 14, 2019 at 09:42:44AM +1100, Dave Chinner wrote: > On Thu, Jan 10, 2019 at 09:30:01AM -0500, Kurt Miller wrote: > > For a well behaved block device that has a writeback cache, > > what is the proper behavior of flush when there are more > > then one outstanding flush operations? Is it; > > > > Flush all writes seen since the last flush. > > or > > Flush all writes received prior to the flush including > > those before any prior flush. The requirement is that all write operations that have been completed before the flush was seen are on stable storage. How that is implemented in detail is up to the device. The typical implementation is simply to writeback the whole cache everytime a flush operation is received. > > > > For example take the following order of requests presented > > to the block device: > > > > writes 1-5 > > flush 1 > > write 6 > > flush 2 > > > > Can flush 2 finish with success as soon as write 6 is flushed > > (which may be before flush 1 success)? Or must it wait for > > all prior write operations to flush (writes 1-6)? No. For all the usual protocols as well as the linux kernel semantics there is no overall command ordering, especially as there is no way to even enforce that in a multi-queue environment. > > * C1. At any given time, only one flush shall be in progress. This makes > * double buffering sufficient. Very specific implementation detail inside the request layer. > Then flush 1 does not guarantee any of the writes are on stable > storage. They *may* be on stable storage if the timing is right, but > it is not guaranteed by the OS code. Likewise, flush 2 only > guarantees writes 1, 3 and 5 are on stable storage becase they are > the only writes that have been signalled as complete when flush 2 > was submitted. Exactly.
