> > If the narrower type is signed it is probably even more confusing!
> > The high bits will be preserved unless you are masking off bit 31.
>
> Yes. However, that case doesn't trigger with the normal case of small
> values. So "~4" works fine with widening, in a way that "~4u" does
> not.
Thinks ... converting:
foo &= ~bar;
to:
foo = ~(~foo | bar);
would generally DTRT.
Whether the compiler has the relevant patterns to optimise
it is another question.
David
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