On Thu, Feb 23, 2023 at 09:41:01PM +0100, Ard Biesheuvel wrote: > This means that a KASLR offset of less than 2 MiB is simply the product > of this physical displacement, and no randomization has actually taken > place. Currently, we use 'kaslr_offset() > 0' to decide whether or not > randomization has occurred, and so we misidentify this case. Making an explicit function to check if we've enabled KASLR is also a nice cleanup in itself. Reviewed-by: Mark Brown <broonie@xxxxxxxxxx>
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