Re: [PATCH v2 3/4] x86/efi: print size and base in binary units in efi_print_memmap

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On Thu, 21 Jan 2016 17:22:31 +0200 Andy Shevchenko <andriy.shevchenko@xxxxxxxxxxxxxxx> wrote:

> From: Robert Elliott <elliott@xxxxxxx>
> 
> Print the base in the best-fit B, KiB, MiB, etc. units rather than
> always MiB. This avoids rounding, which can be misleading.
> 
> Use proper IEC binary units (KiB, MiB, etc.) rather than misuse SI
> decimal units (KB, MB, etc.).
> 
> old:
>     efi: mem61: [Persistent Memory  |   |  |  |  |  |  |   |WB|WT|WC|UC] range=[0x0000000880000000-0x0000000c7fffffff) (16384MB)
> 
> new:
>     efi: mem61: [Persistent Memory  |   |  |  |  |  |  |   |WB|WT|WC|UC] range=[0x0000000880000000-0x0000000c7fffffff] (16 GiB)

hm,

> @@ -225,21 +235,20 @@ int __init efi_memblock_x86_reserve_range(void)
>  void __init efi_print_memmap(void)
>  {
>  #ifdef EFI_DEBUG
> -	efi_memory_desc_t *md;
>  	void *p;
>  	int i;
>  
>  	for (p = memmap.map, i = 0;
>  	     p < memmap.map_end;
>  	     p += memmap.desc_size, i++) {
> -		char buf[64];
> +		efi_memory_desc_t *md = p;
> +		u64 size = md->num_pages << EFI_PAGE_SHIFT;
> +		char buf[64], buf3[32];
>  
> -		md = p;
> -		pr_info("mem%02u: %s range=[0x%016llx-0x%016llx] (%lluMB)\n",
> +		pr_info("mem%02u: %s range=[0x%016llx-0x%016llx] (%s)\n",
>  			i, efi_md_typeattr_format(buf, sizeof(buf), md),
> -			md->phys_addr,
> -			md->phys_addr + (md->num_pages << EFI_PAGE_SHIFT) - 1,

Where did this " - 1" come from?  I can't find a tree which has this.

> -			(md->num_pages >> (20 - EFI_PAGE_SHIFT)));
> +			md->phys_addr, md->phys_addr + size - 1,

So I did s/ - 1// here, but worried.

> +			efi_size_format(buf3, sizeof(buf3), size));
>  	}
>  #endif  /*  EFI_DEBUG  */
>  }

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