Edgar Toernig wrote: > Manu Abraham wrote: >>Allan Stirling wrote: >>>If I change this to >>> >>> p_program_descriptor->program_number = >>> ( buf[pos + 0] << 8) | buf[pos + 1]; >>> >>This would be wrong however, since if you left shift an 8 bit buffer by >>8 all you will get is 0. > > The code is fine as long as buf is unsigned. There's no 8-bit > arithmetic in C - chars are always expanded to ints. And btw, > shifting by the width of the (expanded) left operand is undefined, > not 0. I believe uint8_t is 8 bits and u8 too .. i don't use char's in the code .. Take a look at ca_set_pmt() in dst_ca.c What i am using is 1) u16 var | u8 var 2) u16 var << 8 3) u16 var | u8 var Manu
