I find a logical error in an if statement '(X & 0xfc) == 0x3' is always false After pointing this out, Larry Finger informed what would be the correct one. '(X & 0x3) == 0x3' Signed-off-by: Rickard Strandqvist <rickard_strandqvist@xxxxxxxxxxxxxxxxxx> --- drivers/staging/rtl8821ae/rtl8821ae/hw.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/drivers/staging/rtl8821ae/rtl8821ae/hw.c b/drivers/staging/rtl8821ae/rtl8821ae/hw.c index 1b8583b..52322e3 100644 --- a/drivers/staging/rtl8821ae/rtl8821ae/hw.c +++ b/drivers/staging/rtl8821ae/rtl8821ae/hw.c @@ -1623,7 +1623,7 @@ static int _rtl8821ae_set_media_status(struct ieee80211_hw *hw, rtl_write_byte(rtlpriv, (MSR), bt_msr); rtlpriv->cfg->ops->led_control(hw, ledaction); - if ((bt_msr & ~0xfc) == MSR_AP) + if ((bt_msr & MSR_AP) == MSR_AP) rtl_write_byte(rtlpriv, REG_BCNTCFG + 1, 0x00); else rtl_write_byte(rtlpriv, REG_BCNTCFG + 1, 0x66); -- 1.7.10.4 _______________________________________________ devel mailing list devel@xxxxxxxxxxxxxxxxxxxxxx http://driverdev.linuxdriverproject.org/mailman/listinfo/driverdev-devel
