Andy Shevchenko, le Tue 09 Apr 2013 15:13:09 +0300, a écrit :
> > > + if (*p1 == 'x' && !hex2bin(&num, p1 + 1, 1)) {
> >
> > Count should be 2, shouldn't it?
>
> Actually, no. It means bytes in the result.
Ah, right.
> If I got it correctly the original code translates '\xNN' into NN which
> is exactly one byte.
Yes.
Samuel
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